function error removal

def my_func():
	input_pressure = float(input("Enter pressure in psi: "))
	print("Value inside function:",input_pressure)
# conv_press = input_pressure/14.6;
print("Value outside function:",+input_pressure/14.6)
Show comments

Submit an answer

This textbox defaults to using Markdown to format your answer.

You can type !ref in this text area to quickly search our full set of tutorials, documentation & marketplace offerings and insert the link!

Sign In or Sign Up to Answer

These answers are provided by our Community. If you find them useful, show some love by clicking the heart. If you run into issues leave a comment, or add your own answer to help others.

Want to learn more? Join the DigitalOcean Community!

Join our DigitalOcean community of over a million developers for free! Get help and share knowledge in Q&A, subscribe to topics of interest, and get courses and tools that will help you grow as a developer and scale your project or business.

Hi there,

Usually, variables defined inside a specific function are not accessible outside of that function.

This should work with the following syntax by attaching the variable to an object so it could be accessible outside of the function:

def my_func():
    my_func.input_pressure = float(input("Enter pressure in psi: "))
    print("Value inside function:",my_func.input_pressure)

print("Value outside function:",+my_func.input_pressure/14.6)

Hope that this helps. Regards, Bobby