How to pass parameters to file path? This is what I'm trying to do:
*/2 * * * * /usr/bin/php /var/www/mysite/public_html/cron/cron.php?group=3 >> /var/www/mysite/public_html/cron/cron.log 2>&1
I also tried without the question mark '?' but the cron does not run.
*/2 * * * * /usr/bin/php /var/www/mysite/public_html/cron/cron.php?group=3 >> /var/www/mysite/public_html/cron/cron.log 2>&1
To to pass the parameter?
Thanks
Generally you would not use this method to pass parameters to a CLI PHP script. Instead you would do something like:
*/2 * * * * /usr/bin/php /var/www/mysite/public_html/cron/cron.php 3 >> /var/www/mysite/public_html/cron/cron.log 2>&1
Using $argv[0] to get the value inside your script.
Actually $argv[0] returns path to the script, passed arguments are available at $argv[1], $argv[2], $argv[3] and so on.
php /home/user/script.php some_argument secret_key other_argument
echo $argv[0]; // /home/user/script.php
echo $argv[1]; // some_argument
echo $argv[2]; // secret_key
echo $argv[3]; // other_argument
As the file is inside the public_html directory you can also use curl to issue a HTTP request via URL:
*/2 * * * * curl -s http://example.com/cron/cron.php?group=3 >> /var/www/mysite/public_html/cron/cron.log 2>&1