Python 3 codes for loops

Maybe just try adding additional if statement and if there are no subsequent row to compare just add a default value.

If you wish you could share some of the data that you are running this against so that I could test it as well as it is very hard to just imagine the result without seeing any data.

Heya,

It seems that you want to compare each row with every subsequent row in your “alignments” list and append it somewhere, and you’re having trouble because the last row doesn’t have any rows after it to compare with. This behaviour is due to the nature of your for loop which compares the current row with the next ones, and hence the last row has no subsequent row to be compared.

If you want to include the last row in your “uniques” list regardless of comparison, you can simply append it after the loop. Here is the modified code:

uniques = []
ap = open(tempparse, 'w')

for row in range(len(alignments)):
    ap.write('row '+str(row)+'\n')
    for compare in range(row+1,len(alignments)):
        # Your comparison and appending logic here
        # If some condition is met, add the row or compare index to uniques
        # For example: uniques.append(alignments[row])

# After the loop ends, check if the last row is already in uniques.
# If not, append it.
if alignments[-1] not in uniques:
    uniques.append(alignments[-1])

ap.close()

Please modify the comparison and appending logic as per your needs.

NOTE: It’s highly recommended to use with open(tempparse, 'w') as ap: instead of ap = open(tempparse, 'w'). This ensures that the file is properly closed after it is no longer needed. Here is how you can use it:

with open(tempparse, 'w') as ap:
    for row in range(len(alignments)):
        ap.write('row '+str(row)+'\n')
        # Rest of the code

With this modification, you don’t need to call ap.close(), as it will be done automatically when the with block is exited.