Question

Syntax error near unexpected token `done'

  • Posted May 18, 2014

Hi all,

Sorry for a noob question, I’m jus started with Linux today :D My droplet used CentOS 6.5. I have a script name “loop.sh” with this code:

#!/bin/bash while : do sl done

When I try to run it with command “bash loop.sh” there’s error: syntax error near unexpected token `done’.

What can I do now? Please help.

Thank you so much.

Subscribe
Share

Submit an answer
You can type!ref in this text area to quickly search our full set of tutorials, documentation & marketplace offerings and insert the link!

These answers are provided by our Community. If you find them useful, show some love by clicking the heart. If you run into issues leave a comment, or add your own answer to help others.

I copied and created new file with the code in example of the link: <br> <br>#!/bin/bash <br>COUNTER=0 <br>while [ $COUNTER -lt 10 ]; do <br>echo The counter is $COUNTER <br>let COUNTER=COUNTER+1 <br>done <br> <br>Nothing changed! There’s error: <br>line 6: syntax error near unexpected token `done’ <br> <br>Why bash programing is too hard???

You need a condition for the while loop. See the examples in the link I gave you above. <br>

I replaced : with ; then got another error <br>syntax error near unexpected token `;’

Replace : with ; <br>See here for more examples <br>http://tldp.org/HOWTO/Bash-Prog-Intro-HOWTO-7.html