By ErikRobles
Hello. If I wanted to filter an array and return only strings that contain the string ’ de ', How can I do that? I have the following but it only returns me the contents of the entire array:
let de = 'de ';
let newArr = streets.filter((street) => (street, de));
console.log(newArr);
Any help on this would be super. Thank you.
the array is as follows:
const streets = [
'Boulevards of Paris',
'City walls of Paris',
'Thiers wall',
'Wall of Charles V',
'Wall of Philip II Augustus',
'City gates of Paris',
"Haussmann's renovation of Paris",
'Boulevards of the Marshals',
'Boulevard Auguste-Blanqui',
'Boulevard Barbès',
'Boulevard Beaumarchais',
"Boulevard de l'Amiral-Bruix",
'Boulevard Mortier',
'Boulevard Poniatowski',
'Boulevard Soult',
'Boulevard des Capucines',
'Boulevard de la Chapelle',
'Boulevard de Clichy',
'Boulevard du Crime',
"Boulevard du Général-d'Armée-Jean-Simon",
'Boulevard Haussmann',
"Boulevard de l'Hôpital",
'Boulevard des Italiens',
'Boulevard Lefebvre',
'Boulevard de la Madeleine',
'Boulevard de Magenta',
'Boulevard Malesherbes',
'Boulevard Marguerite-de-Rochechouart',
'Boulevard Montmartre',
'Boulevard du Montparnasse',
'Boulevard Raspail',
'Boulevard Richard-Lenoir',
'Boulevard Saint-Germain',
'Boulevard Saint-Michel',
'Boulevard de Sébastopol',
'Boulevard de Strasbourg',
'Boulevard du Temple',
'Boulevard Voltaire',
'Boulevard de la Zone',
];
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Hi @ErikRobles,
There are multiple ways to do so but here is how I’ll do it:
const substring = 'de';
const matches = streets.filter(element => {
if (element.indexOf(substring) !== -1) {
return true;
} });
console.log(matches);
The function passed to the streets.filter method gets invoked with each element in the array, regardless if the condition is satisfied.
This is useful in case you have multiple elements in the array that satisfy the condition and you need all of their values.
In the if statement we’ve used the String.indexOf method. If the substring is contained in the string, the method returns the index of the match. If it isn’t, the method returns -1.
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