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I have a basic upstart script in /etc/init that is used to run a python script upon system startup/reboot.
description "simple python script"
start on runlevel [2345]
stop on runlevel [06]
respawn
env MY_ENVIRONMENT_VAR='/path/to/file.config'
chdir /path/to/script/
exec python script.py
How would I achieve the same thing using the systemd service management system in Ubuntu 16.04?
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Figured it out - here’s the equivalent systemd script:
[Unit]
Description=simple python script
[Service]
Environment= MY_ENVIRONMENT_VAR =/path/to/file.config
WorkingDirectory=/path/to/script
ExecStart=/usr/bin/python script.py
Restart=always
[Install]
WantedBy=multi-user.target
This file was in my app directory, so I created a dynamic link to it in the systemd directory:
/etc/systemd/system/
by doing:
ln -s /path/to/file/my_systemd_script.service /etc/systemd/system/my_systemd_script.service
If you get a “Too many levels of symbolic links” error: See @nabito answer below, just copy the file into the /etc/systemd/system/ folder with a cp instead of creating a symbolic link.
Then I can start it with:
systemctl daemon-reload
systemctl enable my_systemd_script.service
systemctl start my_systemd_script.service
Thanks, for this conversation i have same problem and i have resolved it but i also want to have a log file for that python script so is there any way to add log file??
Thanks for the tip, however I followed your steps and got an error due to symlink the .service when trying to ‘systemctl enable my_systemd_script.service’
Failed to execute operation: Too many levels of symbolic links.
This is in Ubuntu 16.04.1 LTS upgraded from 14.04. The solution I took is to put the actual .service in /etc/systemd/system. Seems systemctl will try to create another symlink for it, as seen in the success output from ‘systemctl enable’ command.
Created symlink from /etc/systemd/system/multi-user.target.wants/mysystemd.service to /etc/systemd/system/mysystemd.service.
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