I have the following setup:
FrontEnd folder views.py
:
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def home_page(request):
return HttpResponse("New App")
FrontEndfolder urls.py
:
from django.urls import path
from . import views
urlpatterns = [
path('home/', views.home_page, name='home_page'),
]
Main Project folder urls.py
:
from django.contrib import admin
from django.urls import path,include
urlpatterns = [
path('', include('FrontEnd .urls')),
path("admin/", admin.site.urls),
]
However I can’t open http://localhost:8000.
This textbox defaults to using Markdown to format your answer.
You can type !ref in this text area to quickly search our full set of tutorials, documentation & marketplace offerings and insert the link!
These answers are provided by our Community. If you find them useful, show some love by clicking the heart. If you run into issues leave a comment, or add your own answer to help others.
Sign up for Infrastructure as a Newsletter.
Working on improving health and education, reducing inequality, and spurring economic growth? We'd like to help.
Get paid to write technical tutorials and select a tech-focused charity to receive a matching donation.
Heya,
The error you’re encountering is because Django is unable to find a URL pattern that matches the root path (i.e.,
http://127.0.0.1:8000/
). In your ``Project folderurls.py
, you’ve included the URLs from your FrontEnd folderurls.py
under the path''
, which means it’s expecting additional path information to match the defined URL patterns.In your FrontEnd folder
urls.py
, you’ve defined a URL patternhome/
, which means the viewhome_page
in your app will respond tohttp://127.0.0.1:8000/home/
, but there’s no URL pattern defined for the root pathhttp://127.0.0.1:8000/
.To resolve this, you can define a URL pattern in your project’s
urls.py
for the root path. For example:This will make the
home_page
view respond tohttp://127.0.0.1:8000/
.