Exclude lines with directory path

Question

Hello, I have a TXT file that contains the following example data:

./aa
./bb/data
./cc/files/docs

I need to remove all lines from it that contain subdirectories. So in the example above, only the first line should remain. Do you know how to do this in Linux console?

Regards

Answer 1

bobbyiliev September 23, 2021

Hello,

If I get this correctly, you want to have only the base directories without the subdirectories. This could be achieved with awk:

cat old.txt  | awk -F'/' '{ print $2 }' | sort | uniq

Output:

aa
bb
cc

Regards,
Bobby

Reply Report

MichalGiza September 24, 2021

It works, but I need to list directories from this file that are without subdirectories. So in my question example, it will only be ./aa
Reply Report
- bobbyiliev September 24, 2021
  
  Hello,
  
  In this case, what you could do is strip down the first part ./ with sed and then use grep -v to exclude all results that contain a /:
  
  cat dirs.txt | sed -e 's#\./##g' | grep -v '/'
  
  Output:
  
  aa
  
  Best,
  Bobby
  
  Reply Report
  
  MichalGiza September 24, 2021
  
  Works perfectly. Thank you so much!
  
  Regards,
  Michał
  
  Reply Report
  
  bobbyiliev September 24, 2021
  
  Hi Michał,
  
  No problem! Happy to hear that it’s all working!
  
  Best,
  Bobby
  
  Reply Report

Answer 2

MichalGiza September 24, 2021

It works, but I need to list directories from this file that are without subdirectories. So in my question example, it will only be ./aa
Reply Report
- bobbyiliev September 24, 2021
  
  Hello,
  
  In this case, what you could do is strip down the first part ./ with sed and then use grep -v to exclude all results that contain a /:
  
  cat dirs.txt | sed -e 's#\./##g' | grep -v '/'
  
  Output:
  
  aa
  
  Best,
  Bobby
  
  Reply Report
  
  MichalGiza September 24, 2021
  
  Works perfectly. Thank you so much!
  
  Regards,
  Michał
  
  Reply Report
  
  bobbyiliev September 24, 2021
  
  Hi Michał,
  
  No problem! Happy to hear that it’s all working!
  
  Best,
  Bobby
  
  Reply Report

Answer 3

JonsJava September 23, 2021

Sure. This might not be the best solution, but it is one that will work!

Setting up my test:

➜  ~ mkdir test3
➜  ~ cd test3
➜  test3 mkdir -p aa bb/data cc/files/docs

testing my solution:

➜  test3 for i in $(find . -type d -links 2|sed -e 's/\.//g'); do dirs=$(basename $i); clean_i=$(echo $i|sed -e 's/\///g'); if [[ "$dirs" == "$clean_i" ]]; then; echo $clean_i;fi;done
aa

again, I’m sure there is something simpler out there, but this does do the job.

Solution:

for i in $(find . -type d -links 2|sed -e 's/\.//g'); do
  dirs=$(basename $i)
  clean_i=$(echo $i|sed -e 's/\///g')
  if [[ "$dirs" == "$clean_i" ]]; then
    echo $clean_i
  fi
done

Reply Report

MichalGiza September 23, 2021

Thank you, but I asked how to list directories without subdirectories from a text file
Reply Report
- JonsJava September 23, 2021
  
  should be simple enough. Just change the conditional in the for block:
  
  for i in $(cat test.txt)
  
  Reply Report
  
  MichalGiza September 23, 2021
  
  So my script looks like this:
  
  for i in $(cat old.txt); do dirs=$(basename $i) clean_i=$(echo $i|sed -e 's/\///g') if [[ "$dirs" == "$clean_i" ]]; then echo $clean_i fi done
  
  but I’m getting:
  
  . 12.08.2019 - Source Code - Source - Source - Source ...
  
  Reply Report
  
  JonsJava September 23, 2021
  
  I used your examples for testing. With the spaces, my code won’t work.
  
  Reply Report

Answer 4

MichalGiza September 23, 2021

Thank you, but I asked how to list directories without subdirectories from a text file
Reply Report
- JonsJava September 23, 2021
  
  should be simple enough. Just change the conditional in the for block:
  
  for i in $(cat test.txt)
  
  Reply Report
  
  MichalGiza September 23, 2021
  
  So my script looks like this:
  
  for i in $(cat old.txt); do dirs=$(basename $i) clean_i=$(echo $i|sed -e 's/\///g') if [[ "$dirs" == "$clean_i" ]]; then echo $clean_i fi done
  
  but I’m getting:
  
  . 12.08.2019 - Source Code - Source - Source - Source ...
  
  Reply Report
  
  JonsJava September 23, 2021
  
  I used your examples for testing. With the spaces, my code won’t work.
  
  Reply Report

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