Find the second highest number using looping in python.

Hi there,

Here is another option to what has already been mentioned:

list = [9, 6, 4, 10, 13, 2, 3, 5]
max = float('-inf')
second_last = float('-inf')
for x in list:
    if x > max:
        second_last = max
        max = x
    elif x > second_last and x != max:
        second_last = x

print(second_last)

Hope that this helps!

Best,

Bobby

Hi @kayakokulaanusha,

There is no need to loop, I assume you get these numbers from an array? Then you can sort them and get the second element. Something like this:

list_numbers = [24, 10, 60, 25, 9]  
# sorting the list  
list_numbers.sort()  
print("The second largest element of the list is:", list_numbers[-2])