Python string supports slicing to create substring. Note that Python string is immutable, slicing creates a new substring from the source string and original string remains unchanged.
Python slice string syntax is:
str_object[start_pos:end_pos:step]
The slicing starts with the start_pos index (included) and ends at end_pos index (excluded). The step parameter is used to specify the steps to take from start to end index. Python String slicing always follows this rule: s[:i] + s[i:] == s for any index ‘i’. All these parameters are optional - start_pos default value is 0, the end_pos default value is the length of string and step default value is 1. Let’s look at some simple examples of string slice function to create substring.
s = 'HelloWorld'
print(s[:])
print(s[::])
Output:
HelloWorld
HelloWorld
Note that since none of the slicing parameters were provided, the substring is equal to the original string. Let’s look at some more examples of slicing a string.
s = 'HelloWorld'
first_five_chars = s[:5]
print(first_five_chars)
third_to_fifth_chars = s[2:5]
print(third_to_fifth_chars)
Output:
Hello
llo
Note that index value starts from 0, so start_pos 2 refers to the third character in the string.
We can reverse a string using slicing by providing the step value as -1.
s = 'HelloWorld'
reverse_str = s[::-1]
print(reverse_str)
Output: dlroWolleH
Let’s look at some other examples of using steps and negative index values.
s1 = s[2:8:2]
print(s1)
Output: loo
Here the substring contains characters from indexes 2,4 and 6.
s1 = s[8:1:-1]
print(s1)
Output: lroWoll
Here the index values are taken from end to start. The substring is made from indexes 1 to 7 from end to start.
s1 = s[8:1:-2]
print(s1)
Output: lool
Python slice works with negative indexes too, in that case, the start_pos is excluded and end_pos is included in the substring.
s1 = s[-4:-2]
print(s1)
Output: or
Python string slicing handles out of range indexes gracefully.
>>>s = 'Python'
>>>s[100:]
''
>>>s[2:50]
'thon'
That’s all for python string slice function to create substring.
You can checkout complete python script and more Python examples from our GitHub Repository.
Thanks for learning with the DigitalOcean Community. Check out our offerings for compute, storage, networking, and managed databases.
While we believe that this content benefits our community, we have not yet thoroughly reviewed it. If you have any suggestions for improvements, please let us know by clicking the “report an issue“ button at the bottom of the tutorial.
Sign up for Infrastructure as a Newsletter.
Working on improving health and education, reducing inequality, and spurring economic growth? We'd like to help.
Get paid to write technical tutorials and select a tech-focused charity to receive a matching donation.
Plz tell me the slice of ‘HeloWr’
- Aadi
TheData = [20, 3, 4,8,12, 99,4, 26 , 4 ] TheData1= TheData [ 0 : len(TheData) : 1 ] def InsertionData (TheData1): for Count in range(0, len(TheData1)): DataToInsert = TheData1(Count) Inserted = 0 Nextvalue = Count - 1 while (Nextvalue >= 0 and Inserted != 1): if DataToInsert < TheData1(Nextvalue): TheData1(Nextvalue + 1) == TheData1(Nextvalue) Nextvalue = Nextvalue -1 TheData1(Nextvalue +1 ) == DataToInsert else: Inserted = 1 def printarray(TheData1): for count in range(0, len(TheData1)): print(TheData1(count) ) print("Array before sorting \n ") printarray(TheData1) InsertionData(TheData1) print(“Array After sorting \n”) printarray(TheData1) Error: Array before sorting Traceback (most recent call last): File “c:\Users\Admin\Desktop\Paper 4 solution.py”, line 26, in printarray(TheData1) File “c:\Users\Admin\Desktop\Paper 4 solution.py”, line 23, in printarray print(TheData1(count) ) TypeError: ‘list’ object is not callable Anyone help how to done slicing in python
- malik
what does s(5:5) return
- pradeep
Your idea about reverse a string using a negative value is completely wrong please update this post. What actually happening here is x = ‘H e l l o w o r l d’ -----0 1 2 3 4 5 6 7 8 9 >>> x[8:1:-1] output – ‘ l r o w o l l ‘ -------8 7 6 5 4 3 2 Usually, the second parameter 1 won’t be taken into consideration right. This means if I enter x[1:8], index 8 won’t be sliced right. Similarly, this happens in x[8:1:-1]. So index 1 won’t be sliced. >>> x[-2:-8:-1] output- ‘lrowol’ Here, -2,-3,-4,-5,-6,-7 indexes will be sliced. Conclusion: string[x:y:p] When p x>y and index y won’t be sliced. That’ it!!!
- Kobinarth Panchalingam
please alter your article : the negative indexing is wrong
- mostafa
For the negative count, the end of the string starts from -1 not 0. It is like -4 -3 -2 -1 not -4 -3 -2 -1 0
- Coder
Hi I have a doubt: string = “Hi There” print (string[-4:-2]) and the output is ‘he’ but shouldn’t the output be ‘eh’? I am unable to understand why the output is showing he
- Kalpit
Can you explain the last one a little bit? s[-4:-2] Thanks!
- Enoc
Hi Thankx for this section. I need more clarification on s1 = s[8:1:-1] print(s1) Output: lroWoll I am unable to get it .
- sradhanjali behera
thanks pankaj!!!
- curry lover 68